Home › Forums › General Forums › Methodology › FTY=e-DPU
This topic contains 9 replies, has 9 voices, and was last updated by MBBinWI 3 months, 2 weeks ago.
I am confused as to how to obtain the FTY using a constant e-2.718 can someone enlighten me?
i.e.
FTY= e -DPU
e-2.718
FTY=2.718 -0.3
FTY=0.741
FTY=74%
How did this get calculated? HELP!
Do some research on the Poisson equation, this site or elsewhere.
True, also needed a elaborated question. Self study here, will save you time.
I believe this formula is referring to RTY not FTY if memory serves, and obtaining it involves simply taking the natural log (e^x) of the negative dpu measure. – it took me three key strokes on the calculator.
just one state RTY=FTY if defect=0
and as I know RTY= e -DPU when we would like to calculate as a short term but long term you should to multiplication every DPU for each process.
You probably already figured this out, but … The exercise to figure FTY uses an exponent for DPU, expressed as a negative. So your expression
FTY= e (constant) -DPU (to the power expressed)
e-2.718
FTY=2.718 -0.3 (power of negative .3)
FTY=0.741
FTY=74%
I don’t have a scientific calculator so I used Excel, where the formula is shown as “=POWER(2.718,-0.3)”
It’s RTY….not FTY.
….well Chris, I suppose if the production line was moving really fast you might be able to get the product airborne in which case it would be flying and not rolling…. :-)
LOL…..
How about this kind of flying item?
@rbutler – Good one, Robert. You’re getting punnier, and punnier all the time!
@cseider – One of the more bizzaro sitcoms – even for its day. Seriously, the lift to weight ratio for a habit that size would at best lift a midget, I don’t care how little Sally Field weighed. And no vertical stabilizers? Please, totally aerodynamically infeasible, totally unstable (but then, maybe that was a metaphor for Sally?).
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