Amit Kumar Ojha


  • Yes Tracy.

    You are right. No success in this case means 0 defects and 1 success implies 1 defect.
    Success on single trial of 0.1 means that if you test a sample of 100 units what is the probability of getting 10 defects.

    Hope I clarified your doubt :-))

    Best of Luck!!! 7 years, 4 months ago

  • Hi,

    by 1 proportion test for determining sample size what exactly do you imply ? Sorry I dint get that :-( 7 years, 4 months ago

  • Hi John,

    Please find below the solution for the given problem:
    It is given that

    Tolerance = 10
    Alpha = 0.05 and Hence Z = 1.96
    Standard Deviation corresponding to 3.4 parts per million defect rate = 6
    Hence Sample Size = ((1.96*6)/10)^2 = 32.14

    So you need a sample of size = 33 (Rounded Off)

    Good Luck !!! 7 years, 4 months ago

  • Hi All,

    It would be great if someone can throw some light on the difference between Regression and Design of Experiment(DOE) w.r.t their application along with some real time experiences where these have been used in Six Sigma projects. 7 years, 4 months ago

  • I think the basic difference between education and training is in terms of the objective and the way they are done. The fundamental purpose of education is learning and growth whereas that of training is improving the performance of the trainee through teaching him / her the skills required to perform a job perfectly.
    Education encompasses…[Read more]

  • Norbert shared a very simple way by which you can get the answer without getting into complexity of calculating the probabilities.

    In the above problem, since the calculations were not so tedious, hence you can do either way. However, in many real life scenarios the calculations are too complicated to be done manually.

    Hence it is good to use…[Read more]

  • I Agree with JB. Better use the same period before and after for showing the data in SPC chart and use simple Box Plot to compare the peformance befor and after. 7 years, 4 months ago

  • Hi,

    The correct answer is D(0.9662)

    Here is the solution….
    First of all consider this as a problem of Binomial Distribution. Our objective is to find the probability of getting 2 or more defects (thats when the lot will be rejected).
    Technically we can write it as P(X>=2)
    It is given in the problem that X is no. of defects, n=50, p=0.1,…[Read more]

  • ASQ is widely recognized. Also regarding the reference material, you may need to refer more than one book.

    Try to find out topic wise books.
    For Advanced Statistic you may use Levin & Rubin – Statistics for Management
    In general The certified Six Sigma Black Belt Handbook by Kubaik is good reference material. pls note that it has few printing…[Read more]

  • One more point, please do not limit the scope of the analysis by presuming the cause as having too many vendors.

    Many a times I have observed that, post thorough root cause analysis, it is found that the cause which was presumed is actually not a very significant one.

    I suggest let us go step by step as per DMAIC methodology. 7 years, 4 months ago

  • So in this case the real pain area is delay in getting the stuffs. Now I suggest you to quantify the problem as in how much time does it take on an average and how is it negatively affecting the business in terms of causing further delay to other activities or loss of sale etc.
    Once you are done with this, we are good to go with the problem…[Read more]

  • The hierarchy Yellow-Green-Black-MBB is made to indicate the increasing depth and scope of the tools and their application. If you feel that you understood the tools very well and can relate how it is applied in different situation, you may skip a level.
    However before you skip pls make sure that you do not miss any basic concept so that you find…[Read more]

  • I suggest you to first try to link the strategic objective with operation goal and also keep in mind that there many variation and tools in Six Sigma. The application of tools depends upon your objective as well as the scenario.

    Good Luck !!! 7 years, 4 months ago

  • Agree with Shelby’s point regarding scope finalization.
    Its very important to finalize on the following points along with concurrence from your friend.
    Try to think of the following points:
    1. Business Problem
    2. Goal
    3. In scope / Out of Scope
    4. Timelines
    If you planning to do it phase wise than think of phase wise plan… 7 years, 4 months ago

  • Start with the Value Stream Map. Try to look for the areas where most of the cost is incurred or cycle time / efforts are involved. Then try to do a root cause analysis so as to find the reason for the inefficiency. Techniques such as pareto analysis along with fishbone diagram would help you see the real pain.

    Then try to come up with…[Read more]

  • Hi Hmalfedel,

    Can you exactly state what is the problem your friend is facing with two many vendors. Try to focus on the pain area and then start quantifying it. Having two many vendors can not be a problem statement as it does not specify the real pain area.

    Hope it helps !!! 7 years, 4 months ago

  • I agree with Don Strayer. In IT/Software industry DFSS is more applicable than DMAIC. DMAIC basically applies when you have a process which you want to improve however, in case of product/process design DFSS is used to pro-actively optimize the design at the initial stages in order to fulfill customer requirements.
    The suitability of DFSS for…[Read more]

  • Hi All,
    Now since the concept of Lean Manufacturing has been embraced by many companies in Service Industry, does anyone have idea about implementation of OEE/OPE in Service Industry and what could be the potential benefits from it. 7 years, 4 months ago

  • According to me, this problem statement would limit the scope of analysis as the cause of the problem is already mentioned.

    Mentioning below few points to be taken care while formulating any problem statement in a Six Sigma project:

    1. It must give the real pain area in terms of quantitative data.
    2. Three aspects must be present in the problem…[Read more]

  • In order to determine the takt time you need to consider the available time which in this case is limited by op2. Hence you may consider 2400 sec as available time to determine takt time. 7 years, 4 months ago

  • Load More