Not a dumb question for some. Some people like to know the history of things – about 25% of the population wants to know the history. It is like asking for the history of Six Sigma. Where did it come from? Why did it work in the past? Does what happened in the past imply it will work in the future? He asked a simple question. If you don’t…[Read more]
Let’s try that code again:Function d2cal(n)Dim StartNum As Long, EndNum As Long, NumPoints As Long, Dx As DoubleDim Int1 As Double, Int2 As Double, i As Long StartNum = -200 EndNum = 200 NumPoints = 1000 Dx = (EndNum – StartNum) / NumPoints Int1 = 1 – (1 – Application.NormSDist(StartNum)) ^ n – (Application.NormSDist(StartNum)) ^ n…[Read more]
I read your article in your continuing debate with Dr. Wheeler. In your real data example, you say:”The example data used in this discussion is a true enterprise view of a business process. This reports the time to change from one product to another on a process line. It includes six months of data from 14 process lines that involved…[Read more]
Thanks for the reply. WHat I’m specifically trying to do is use a simple one-way ANOVA to show equivalence. It’s relatively easy to choose the “zone of indeifference” in a 2 sample equivalence test, since this is a pretty intuitive thing. For example, if I want to prove equivalence between the strength of two different materials, I wo…[Read more]
You are wrong.
3 sigma is only used by that crazy Shewhart – Deming – Wheeler crowd.
In the highly acclaimed and incredibly brilliant Six Sigma, we only use control charts with 6 sigma limits. The psychologist Mikel Harry has proven it to be true.
I disagree on using the p control chart. The probability of attrition is not the same for all employees. For example, younger employees tend to switch jobs more often. Thus, one basic condition for using the binomial distribution for the control limits in the p chart is not met.
I would use an individuals control chart.
Here it is free down load for cqe exam
Kris, good question, more subtle than some realize, Robert and BC have provided the basic math. Remember that if the slope is not statistically signficantly different from zero, then there is not a significant correlation between the x’s and y’s. The algebra provided by BC and Robert make that clear, as b –> 0, r^2 –> 0 too.
If z = 1.85:
The area under the curve to the left of z = 1.85 is found using the following in Excel:
normsdist(1.85) = 0.968
You can also use: normdist(1.85, 0, 1, true) which is for the normal curve wiht average of 0 and standar devation of 1.
For the area under to the curve to the right of z = 1.85 simply use:
1-normsdist(1.85) = 0.032
Just a quick add to RhinoNeil’s response. Several recent articles have been published regarding the iSSSM six sigma maturity model. Easiest place I know to find it is at the Instantis home page or perhaps ISSSP website. Our team has been wrestling with a similar question and has recently begun work to integrate the iSSSM maturity mo…[Read more]
As a motivational speaker and someone with a lot of credibility in the manufacturing field, Mario Perez Wilson is probably the best.
We used another famous individual first, and it was a disaster. Then, an ex-Motorolan recommended we contact Mario and it was unbelievable.
Our Six Sigma program runs flawless. We hired his consulting fir…[Read more]
Why pay for training if you already understand the methodology? You could become GB certified through ASQ – though you might need to find a good Lean Six Sigma text and brush up. Good luck!
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