Binomial Dist.

Note  the   four  conditions  for  applying  a  binomial  distribution:2  states (success/failure?),fixed  # of  trials,trials  are  independent and probability of  success on every trial is the  same (use  the  table  for  finding  the  figure  for  each p,for  example  p(x=3) equal  to .2428 etc,).Don’t  mix  up ,using sd in  the  formula as  it  should  only  include :sample  size,# of  defects and  the  proportion  defective  (p).
Anyhow  the  binomial  distribution mean  and  sd (sigma) can  be  obtained from the  following  calculations:
the  binomial mean=mu=np
the binomial  sigma (sd)=Sigma= np(1-p) -under  the  square  root
ofcourse  you have  to  distinquish between  the mean  and  the  sd.
finally  the  poisson distribution can  be  an  approximation to  the  binomial when p  is  equal to  or  less than 0.1,and  the  sample  size  n is  fairly large
Good  Luck  

You get ‘units’ with continuous data. The binomial disribution is discrete, i.e. there are only two possible outcomes of a single trial, 0 or 1, so there are no units.
When you calculate the mean and the SD of a binomial distribution the ‘units’ are already the same, i.e. there aren’t any, so don’t worry about it.
By the way, the standard error of p is sqrt((p(1 – p)/n)
If you want approximate confidence limits, you can use
p +/- z alpha/2 * s.e.(p)
For 95% C.L.use 1.96*s.e.(p)
Hope this leaves you less doubtful

Wow Idiot,I’m impressed. You gave helpful information to someone.Maybe you aren’t as bad as Darth says.

Thank You Stan.I’m  glad  to  receive  your  positive  comment .