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calculating 3.4dpmo

Six Sigma – iSixSigma Forums Old Forums General calculating 3.4dpmo

Viewing 8 posts - 1 through 8 (of 8 total)
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  • #50312

    Sinnicks
    Participant

    Hi,I’d like to know the mathematics behind where 3.4dpmo was derived from in a six sigma process. During a class in statistical process control a couple of years back this was explained to us. I remember it had something to do with cp,cpk and the normal distribution if i remember correctly. I can’t seem to peice those together right now. Can someone explain to me?thanks,
    mark

    0
    #172909

    GB
    Participant
    #172927

    Sinnicks
    Participant

    thanks!

    0
    #172966

    Edwards
    Participant

    i just told you how to calculate in EXCEL.
    you can copy below formual to EXCEL,
    =normdist(-6,1.5,1,true)+1-normadist(6,1.5,1,true)
    and you will get the answer.
    i am from china,and i am glad find such a great SS forum,i hope i can leran not only the SS ,but also improve my english here.

    0
    #172967

    Edwards
    Participant

    i just told you how to calculate in EXCEL.
    you can copy below formual to EXCEL,
    =normdist(-6,1.5,1,true)+1-normadist(6,1.5,1,true)
    and you will get the answer.
    i am from china,and i am glad find such a great SS forum,i hope i can leran not only the SS ,but also improve my english here.

    0
    #172969

    Stanly
    Member

    Why you don’t use SS to improve the quality of the chineese products??

    0
    #172981

    Edwards
    Participant

    for i am working in a US company.

    0
    #173016

    Saherngu
    Participant

    My understanding as to the “why” is that overtime a normally distributed process is expected to shift approximately 1.5 standard deviation beyond the “normal”.

    0
Viewing 8 posts - 1 through 8 (of 8 total)

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