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Topic Control Chart with Range Calculation

Control Chart with Range Calculation

Home Forums General Forums New to Lean Six Sigma Control Chart with Range Calculation

This topic contains 13 replies, has 6 voices, and was last updated by Profile photo of Chris Seider Chris Seider 2 months ago.

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  • #602010 Reply
    Profile photo of John Peters
    John Peters
    Participant
    Reputation - 39
    Rank - Aluminum

    I’m new to Lean Six Sigma and have been given a question (as seen below) and would really appreciate any help available.

    Question: When using a control chart what would an average of 95.75 show in terms of the range when there was a sample of 20.
    a) 1.0
    b) 0.8
    c) 0.5
    d) 0.6

    Any help would be appreciated and an explanation on how it was worked out would be amazing!
    Thanks in advance.

    John

    #602026 Reply

    @johnpeters123 You’re more likely to get helpful responses if you first explain what you think/why.

    The more details you provide, the better. The iSixSigma audience is helpful, but they like to see that someone is putting forth a good-faith effort first.

    #602030 Reply
    Profile photo of John Peters
    John Peters
    Participant
    Reputation - 39
    Rank - Aluminum

    Hi Katie,

    Yes, sorry i do understand that. But I have no idea how it could be answered with the information provided
    .
    When it states range I would assume that it would refer to the span of the data for the upper and lower control limits. However this just states that the ‘average’ is 95.75 with a sample of 20… so i’m completely unsure how you would go about workout out the range just from these figures.

    Thanks anyway!
    John

    #602038 Reply

    @johnpeters123 What you just wrote is exactly what I meant! :)

    #602058 Reply
    Profile photo of John Peters
    John Peters
    Participant
    Reputation - 39
    Rank - Aluminum

    Hi Katie,

    Thank you, so what you’re saying is it can’t be answered based on the information provided?

    Thanks again!

    #602102 Reply

    it looks like homework here but….

    think of the following. just because you know the center of your data, why would you presume you can describe the variation?

    look at the formulas for your consideration.

    #602103 Reply
    Profile photo of John Peters
    John Peters
    Participant
    Reputation - 39
    Rank - Aluminum

    Wow.

    #602104 Reply

    @johnpeters123 I didn’t answer your question. I suggested a better way of presenting your question that made it more likely you’ll get a reply.

    #602105 Reply
    Profile photo of John Peters
    John Peters
    Participant
    Reputation - 39
    Rank - Aluminum

    Sorry, accidentally hit send. Thanks for your help.

    I’ll look into it.
    No it’s not homework, it’s just revision for my green belt exam.

    Thanks

    #602107 Reply

    If there is a way to answer that question I will have to admit I can’t think of a way to do it. You are correct – the usual problem of this type is to give a min and a max, compute their average and then divide the result by d2 for 20 samples (d2 comes from tables of percentage points of the distribution of the relative range) For 20 samples that would be 3.735.

    I would say that if taken at face value – 95.75 is the mean and 20 is the sample size then there is no way to estimate the standard deviation and even if you did so the statement/question “what would an average of 95.75 show in terms of the range…” doesn’t make any sense.

    A real stretch – If we assume the question implies that the average range is 95.75 then the estimate of the standard deviation based on 20 samples would be 25.6 but that number isn’t close to any of the choices and it still begs the question – what does the phrase “show in terms of the range” mean.

    My guess would be that at least one part of the question went missing in action when it was transcribed.

    #602167 Reply

    @rbutler – or the preparer of the question isn’t all that knowledgeable.

    #602374 Reply

    @MBBinWI Actually I started to post a comment with respect to the overall quality of the test and what it might suggest relative to the quality of the training received. I find this question particularly worrisome since it seems to be the second poorly presented question in the material the OP is using.

    #605289 Reply

    @johnpeters123 That is what happens when you listen to Katie. She has been at this a very long time and knows most of the people who contribute and what will get them to help.

    Your sincerity goes a very long way as well.

    #606079 Reply

    @MBBinWI I’m shocked you’d imply someone put together a test question without understanding nuances and breadth of experience. :)

    Having created customer “loved” BB, MBB, and GB exams I can tell you it’s not easy or trivial.

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