Discrete Mathematics Functions
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 This topic has 14 replies, 8 voices, and was last updated 13 years, 8 months ago by jugnu.

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November 20, 2008 at 4:47 pm #51368
Q:1 If f(x)=x/2+3 and g(x)=3/4x2then find the value of5f(2)7g(4)Q:2 For the real valued function, f defined below Find f^1(1) Wheref(x)=3x^2+7Q:3 The sum of three numbers in A.P is 24 and their product is 440.Find the numbers.
0November 20, 2008 at 6:34 pm #177922Q1) 350
Q2) .10
Q3) ?
0November 20, 2008 at 6:38 pm #177923How did u solve this?
0November 20, 2008 at 6:57 pm #177926Are there 2 RC’s?
0November 20, 2008 at 8:07 pm #177935Q1=25
0November 21, 2008 at 3:13 am #177957Sorry
Q1) 45
Q2) .1
Q3) Don’t know what A.P. means. However as the problem is written you have 3 unknows and two equations.
1. x+y+z=24
2. (x)(y)(z)=440
This type of problem can’t be solved. You need a third equation. Unless of course A.P. has some sort of meaning that helps with solving it.
To solve I just substituted 1,2, and 4 for the x and solved the equations you gave. Hope this helps.0November 21, 2008 at 3:41 am #177959Actually, #3 is solved very easily with intuition.
My question, though: What is the purpose of this? Exam? Homework?0November 21, 2008 at 4:01 am #177960DLW you are right. I guess I didn’t give it the proper amount of thought. The answer is 8, 5, and 11. I should have paid closer attention to my factoring efforts earlier.
Don’t know what it’s for I just like math problems.0November 21, 2008 at 4:17 am #177961RC2,
The “What is the purpose…” question was directed to the OP. While
most of us here probably like math and logic problems (a very good
thing, I think), every once in awhile someone tries to get others to do
homework or even exam problems for them. So solve the problems, if
you must :O) Just don’t give the answers to anyone who does not
deserve them.
DLW – BPEX0November 21, 2008 at 5:04 am #177962I m Sorry my mistake. A.P stands for Arithmetic Progression
0November 21, 2008 at 5:09 am #177963The purpose is to solve assignment.Actually I m not getting the concept. Neither from lectures nor from books. That’s why i asked u peopleIf u can help me then pls do so. I need to know what are the steps to take solving these problems.Thanks & Regards
0November 21, 2008 at 7:22 am #177964Please solved the problem and give a solution as soon as possible.
The sum of three numbers in A.P is 24 and their product is 440.Find the numbers.0November 21, 2008 at 10:34 am #177967The numbers are 5, 8 , 11 . Is it correct ?
0November 21, 2008 at 11:21 am #177969
GourishankarParticipant@Gourishankar Include @Gourishankar in your post and this person will
be notified via email.Jugnu
Here’s my solution :
Assume the 3 nos. are : a , a+n , a+2n
Eq 1 : a + (a+n) + (a +2n) = 24 => a+n = 8
Eq. 2 : a*(a+n)*(a+2n) = 440
Since a+ n = 8 , the eq. 2 becomes : a*(a+2n) =440/8 = 55
The only possible values are : a = 5 & a+2n = 11 , Solve this simple equation and you will get the three no.s in AP as 5 , 8 , 11
Gourishankar
0November 21, 2008 at 11:29 am #177970Thank you very much. You have saved my life
0 
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