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This topic contains 2 replies, has 2 voices, and was last updated by Mihail Sadeanu 1 day, 19 hours ago.

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Alf MHi everyone,

I was wondering if someone could help me understand the question below, the old fashioned way (Paper, Pencil & Calculator).

The DPMO for a process is 860. What is the approximate six sigma level of the process?

6 σ = 0.8406 + √29.37 – 2.221 x ln(860)

=0.8406 + √29.37 -15.01

=0.8406 + 3.7895 = 4.63The result is 4.63

Question: Where 15.01 come from? What calculation ?

I know the 3.785 come from 29.37 -15.01 = 14.36 = √ 3.7895, but where 15.01 come from? Which calculation?

Thanks in advance I will very much appreciate the help.

AlfHave you considered @normsdist and @normsinv with excel. There are normal distribution charts that exist to do it with paper/pencil also.

You are using the normal distribution for converting ppm defective or DPMO to sigma level. There are previous posts on this also.

Hope this helps.

The correct calculation formula is:

Process Sigma = 0.8406 + SQRT(29.37 – 2.221 * (ln(DPMO))) =

0.8406 + SQRT (29.37 – 2.221 * 6.76) = 0,8406 + SQRT (29.37 – 14.9396) = 0.8406 + SQRT (14.4304) = 0.8406 + 3.7987 = 4.6393There is not any 15.01 value.

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