Gauge R/R V %tolerance
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 This topic has 4 replies, 4 voices, and was last updated 8 years, 6 months ago by Usman Mohammad.

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July 5, 2011 at 11:57 am #53838
hoyleParticipant@denis22111 Include @denis22111 in your post and this person will
be notified via email.I have carried out a gauge R/R study see below. The total gauge R/R is 7.82 but my customer has informed me that the study has failed because the %tolerance is above 20%?. The product has a 0.06mm tolerance. What is the %toerance a meassure off?
Thanks in advance for any help.
Denis22111
%Contribution
Source Variance (of Variance)Total Gage R&R 6.74E06 [b]7.82
[ Repeatability 6.74E06 7.82
Reproducibility 0.00E+00 0.00
ParttoPart 7.95E05 92.18
Total Variation 8.62E05 100.00StdDev Study Var %Study Var %Tolerance
Source (SD) (5.15*SD) (%SV) (SV/Toler)Total Gage R&R 2.60E03 1.34E02 27.96 22.29
Repeatability 2.60E03 1.34E02 27.96 22.29
Reproducibility 0.00E+00 0.00E+00 0.00 0.00
ParttoPart 8.92E03 4.59E02 96.01 76.53
Total Variation 9.29E03 4.78E02 100.00 79.710July 7, 2011 at 2:50 pm #191628
PaulonisParticipant@paulonis Include @paulonis in your post and this person will
be notified via email.%Tolerance in Minitab is what people often call the precisiontotolerance ratio. That is, the percentage of the tolerance taken up by the measurement error. In your case, the results are telling you that the measurement error is taking up 22.29% of your total tolerance of 0.06mm (assuming you put everything into Minitab correctly).
I’m not sure what you mean by “the study has failed”. Is the customer saying that your gauge is inadequate because the P/T is > 20% or is there some suggestion that the GR&R study as a whole has “failed” because P/T is > 20%? If it is the latter, I don’t understand that at all. A 20% P/T is very typical. It is no indication of a flawed study.
In your case the 22.29% P/T ratio is on the high side regarding gauge adequacy, especially if you are expecting to get to a high sigma level in your process, but guidelines for P/T are usually set at < 30% with a k of 5.15 like you have. I would not think that this P/T value would indicate an inadequate gauge based on that measure alone.
Overall, with your P/T of 22.29% and your GR&R of 27.96% your process is running at a capability (Cp) of about 1. This corresponds to a sigma level of about 3. Decent, but not great.
You may want to look into a paper by a colleague of mine that does a great job of explaining P/T and GR&R together in a twodimensional analysis. It may help you get a better understanding.
White, T. Kevin, and Connie M. Borror. “Twodimensional Guidelines for Measurement System Indices.” Qual. Reliab. Engng. Int. 27.4 (2011): 47987. Print.
0July 8, 2011 at 6:04 pm #191630If you are familiar with the concept of NDC using study parameters, this is the same requirement using specifications. The calculation is: ndc = 1.41* PV/GRR The desired minimum of ndc > 5 if inverted and changed to a percent is 20%. Dividing 5.15 * GRR by the Specification Spread results in the percent the measurement error uses of the the total specification. The common practice today is to multiply GRR by 6 not 5.15 which would make the percentage even larger.
0April 4, 2014 at 5:32 pm #196828
Usman MohammadParticipant@hillside Include @hillside in your post and this person will
be notified via email.I think the % GageR&% with 10%, 20% 30% rule? and does %contribution 0f 19% means each compote must not be >9% or does it mean the total Gage R&R must be less than 9% (ie. using the variance method)
0April 4, 2014 at 5:36 pm #196829
Usman MohammadParticipant@hillside Include @hillside in your post and this person will
be notified via email.Excuse my earlier Typos
I think the question is can one use % GageR&R under the % contribution (Variance Method) and apply the 10%, 20% 30% rule? and does %contribution 0f 19% means each component must not be >9% or does it mean the total Gage R&R must be less than 9%?0 
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