Help With Cycle Time Problem
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 This topic has 4 replies, 3 voices, and was last updated 8 years, 10 months ago by Chris Seider.

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August 9, 2012 at 9:13 am #54141
RogerGuest@foreverlearning Include @foreverlearning in your post and this person will
be notified via email.10 ct, 8 ct, 0 ct,7 ct,11 ct,3 ct,3 ct,3 ct,5 ct,10 ct…..what is the cycle time (ct) 80% of time? how did u get it? I used this equation below and i was told it was wrong….. do i need to sort the days?
days ppl percent
10 1 10
8 2 20
0 3 30
7 4 40
11 5 50
3 6 60
3 7 70
3 8 80
5 9 90
10 10 1000August 10, 2012 at 4:24 am #193888
Prabhu VParticipant@prabhuvspj Include @prabhuvspj in your post and this person will
be notified via email.Hi,
Can you pls elaborate your query with what is the main objective and others…..
0August 12, 2012 at 1:04 pm #193901
Eric MaassParticipant@poetengineer Include @poetengineer in your post and this person will
be notified via email.Hi Roger,
It sounds like you were given a set of individual cycle time measurements…and they want you to estimate the cycle time 80% of the time…Which is a rather vague request.
If they wanted you to tell them a value that 80% of the cycle time values are less than, then you would want to sort the data, and find the value that 80% are less than.
If they wanted you to assume that cycle times follow a normal distribution, you would use this sample of cycle times to come up with a sample mean and sample standard deviation, and use the normal distribution to estimate the value that 80% of the cycle times are less than.0August 13, 2012 at 9:43 am #193908
manipageGuest@manipage Include @manipage in your post and this person will
be notified via email.Hi Roger, I think the 80% of the time the cycle time will be 3, If it is correct, then you can find this applying simple pareto.
0August 13, 2012 at 10:57 am #193910
Chris SeiderParticipant@cseider Include @cseider in your post and this person will
be notified via email.If you want the maximum cycle time you’d expect 80% of the time, you can add 0.84 times the standard deviation and add to the mean cycle time–if you are comfortable with assuming a normal distribution.
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