iSixSigma

Measuring Association Between Continuous and Categorical Variables

Six Sigma – iSixSigma Forums General Forums Tools & Templates Measuring Association Between Continuous and Categorical Variables

This topic contains 2 replies, has 3 voices, and was last updated by  Chris Seider 9 months, 1 week ago.

Viewing 3 posts - 1 through 3 (of 3 total)
  • Author
    Posts
  • #55951

    Vijay Narayan
    Participant

    Hi,
    For a study I’m planning, I’m not sure of the right way to measure association and/or correlation between 2 variables, where one is a continuous variable (dependent), and the other is dichotomous categorical independent variable (independent).

    The study looks at the relationship between ‘amount of time (# days) it takes for a patient’s blood sample to be processed by the laboratory’ and ‘whether or not the patient actually receives the test/result (yes/no)’. The null hypothesis is that there is no association between # of days to process blood sample in the lab and whether or not patient receives the test result.

    So it is “whether patient receives his/her test results” (dichotomous categorical variable, independent) as a function of “blood sample processing time” (continuous variable, dependent).

    The data is from 422 patients (for each, I have the # days and whether the patient received results). I believe the central limit theorem applies for distribution for sample processing time data points (# days).

    Do you know what statistical test and measure would be most appropriate to assess association and correlation for this situation? Also, is association or correlation the better measure to use?

    Many thanks!

    #202336

    Robert Butler
    Participant

    You posted this same question back on 25 February and we gave you the answer – is this post in error or is there something else you want to know?

    #202354

    Chris Seider
    Participant

    Hope all is well @rbutler !

    Stay warm and safe from ice on the sidewalks!

Viewing 3 posts - 1 through 3 (of 3 total)

You must be logged in to reply to this topic.