# Process Yield Estimation

Six Sigma – iSixSigma › Forums › General Forums › Tools & Templates › Process Yield Estimation

This topic contains 3 replies, has 3 voices, and was last updated by James Heidt 1 year, 1 month ago.

- AuthorPosts
- November 8, 2017 at 1:50 am #55859
Hello everyone,

Quick question, which I can’t seem to find anywhere.

Say I have a process which produces parts with several critical dimensions. In my case 4. From each of those dimensions I can determine a cpk value and a . How can I estimate a total process yield, combining the yields or cpk values from the individual dimensions? I know that there are influences between some dimensions, so I can’t just multiply all individual yields.

Thanks.

November 8, 2017 at 6:49 am #201948sigma squared total = sigma squared of first part plus sigma squared of second part ….if they are linearly connected and you’re looking at total length.

One can predict total ppm defective of final product by adding up ppm defective individually BUT there’s some overlap probably that may be difficult to model.

It’s not an exact method but…

November 9, 2017 at 5:21 am #201951Hi Chris,

Thanks, but unfortunately the measurements are not connected linearly. Translated to an XYZ axis I’m looking at 1 measurement in X, 2 in Y and 1 in Z. And as you say, there’s some overlap (not probably, but surely) in the defective values. Eg, if X becomes larger, there is a significant chance that one of the Y’s is smaller.

In that case the summation of the ppm would be far too pessimistic, I’m afraid.November 17, 2017 at 6:41 am #201978If your objective to take the 4 individual Cpk’s to find an overall process Cpk, the ‘overlap’ would seem to make this a problem. You could try a sample to estimate how many of the parts overlap in defects, and then develop a model of how often one dimension failing leads to other dimensions failing and then test the model for reliability against a sample. But unfortunately I don’t see an easy solution here.

- AuthorPosts

You must be logged in to reply to this topic.