# Pvalue minitab

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• #47141

gt
Participant

i have 12 Df numerator and 2 Df denominator to get Fc of 19.41. in my study i got Fvalue of 18.24.
Minitab is givin me a Pvalue of 0000. So that means : Ha “accepted” meaning statistically there is a difference between factors
If Fc>Fvalue, shouldn’t we “fail in rejecting the null”?
any input is appreciated

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#156831

Jim Shelor
Participant

gt,
If P < alpha, reject the null.
If F statistic > F critical, reject the null.
Your P is < alpha – you reject the null, not fail to reject the null.
I hope this helps
Jim Shelor

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#156833

Jim Shelor
Participant

gt,
Yes, when F stat < Fc, you accept the null.
I have seen a lot of problem like this.  When Fc and F stat are only 5 to 10% different, they can lead to confusion because of roundoff error.
However, sinc your P=.0000, the F should not be that close.  Check your data again and if you want some backup, I can run it for you.
Jim Shelor

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#156834

gt
Participant

this is what i got
One-way ANOVA: results versus pates
Source DF  SS       MS       F     P
pates  2  1.0127  0.5064 18.24 0.000
Error  12  0.3331 0.0278
Total  14 1 .3458

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#156836

Craig
Participant

I believe you have your numerator and denomimator mixed up.
F critical is 3.89 at an alpha of .05

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#156837

Jim Shelor
Participant

gt,
I agree with hacl.
If you run the comparison function
Hsu’s MCB (Multiple Comparisons with the Best)
Family error rate = 0.1
Critical value = 1.87
As you can see, Minitab provides Fc.
Hope this helps.
Jim Shelor

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#156838

Jim Shelor
Participant

That last post was an example, not the answer to your problem for Fc.

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