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Pvalue minitab

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  • #47141

    gt
    Participant

    i have 12 Df numerator and 2 Df denominator to get Fc of 19.41. in my study i got Fvalue of 18.24.
    Minitab is givin me a Pvalue of 0000. So that means : Ha “accepted” meaning statistically there is a difference between factors
    If Fc>Fvalue, shouldn’t we “fail in rejecting the null”?
    any input is appreciated

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    #156831

    Jim Shelor
    Participant

    gt,
    If P < alpha, reject the null.
    If F statistic > F critical, reject the null.
    There is no difference in your answers for the problem.
    Your P is < alpha – you reject the null, not fail to reject the null.
    I hope this helps
    Jim Shelor

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    #156833

    Jim Shelor
    Participant

    gt,
    I am sorry, I misread your question.
    Yes, when F stat < Fc, you accept the null.
    I have seen a lot of problem like this.  When Fc and F stat are only 5 to 10% different, they can lead to confusion because of roundoff error.
    However, sinc your P=.0000, the F should not be that close.  Check your data again and if you want some backup, I can run it for you.
    Sorry about reading the question wrong the first time.
    Jim Shelor

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    #156834

    gt
    Participant

    this is what i got
    One-way ANOVA: results versus pates
    Source DF  SS       MS       F     P
    pates  2  1.0127  0.5064 18.24 0.000
    Error  12  0.3331 0.0278
    Total  14 1 .3458

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    #156836

    Craig
    Participant

    I believe you have your numerator and denomimator mixed up.
    F critical is 3.89 at an alpha of .05

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    #156837

    Jim Shelor
    Participant

    gt,
    I agree with hacl.
    If you run the comparison function
    Hsu’s MCB (Multiple Comparisons with the Best)
    Family error rate = 0.1
    Critical value = 1.87
    As you can see, Minitab provides Fc.
    Hope this helps.
    Jim Shelor

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    #156838

    Jim Shelor
    Participant

    That last post was an example, not the answer to your problem for Fc.

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