Most fairly accurate descriptions of equipment and/or process lifetimes assume that failure rates follow a three period I II III “bathtubcurve pattern” where failures/errors:
I – Decrease during the debugging or improvement time period.
II – Remain relatively constant and at their lowest levels during the normal equipment or process operating period.
III – Increase during the wearout time period.
Scientific studies of limit based natural or complex growth patterns also suggest that many processes are inherently nonlinear and subject to chaotic tendencies. The logistics map^{3} or parabola Xt + 1 = RXt (1Xt) where Xt + 1 the measure of the next generation is a function of the present measure Xt, R is the growth factor and t is a discrete time variable is a simple model for these processes. When the growth factor R falls within the range of 1 < R < 3 the process is stable. For R = 2, the time series iterates Xt = X1 X2 X3… converge to the constant value Xc =.5 which can be easily demonstrated (see Table 1) through the use of an Excel spreadsheet or pocket calculator.
Table 1: Logistics Map – Xt + 1 = Rxt (1Xt) Calculated Iterates  
Process Category  Unstable Decreasing  Stable Constant  Unstable Oscillation  Unstable Oscillation  Unstable Chaotic 
R =  1  2  3  3.24  3.8 
X0  0.800  0.800  0.800  0.800  0.800 
X1  0.160  0.320  0.480  0.518  0.608 
X2  0.134  0.435  0.749  0.809  0.906 
X3  0.116  0.492  0.564  0.501  0.325 
X4  0.103  0.500  0.738  0.810  0.833 
X5  0.092  0.500  0.581  0.499  0.528 
X6  0.084  0.500  0.730  0.810  0.947 
X7  0.077  0.500  0.591  0.499  0.191 
X8  0.071  0.500  0.725  0.810  0.587 
X9  0.066  0.500  0.598  0.498  0.921 
The critical growth factor value Rcr = 3.24 (51/2 +1 ) in Table 1 signals the start of chaotic instability in this model process and for R = 3.8 the instability is clearly evident.
If we assume that variance (Vt) of a process during its lifetime varies between zero and some maximum acceptable value Vm, the application of the logistics parabola model to the process results in the iterate expression Vt + 1 = RVt (Vm – Vt). In this case the process is stable^{1} within the growth factor R range of 1/Vm < R < 3/Vm. Also, the process attains superstability or constancy when its variance equals one half of the maximum acceptable value (Vt = Vm/2) and when R = 2/Vm. This is illustrated for a process with a maximumallowed variance of Vm= 9 (standard deviation =3) in Table 2.
Table 2: Superstable Process Variance Map – Vt + 1 = RVt (9 – Vt)  
Variance Category  Unstable Decreasing  Superstable Constant  Unstable Oscillation  Unstable Oscillation  Unstable Chaotic 
R =  0.111  0.222  0.333  0.360  0.422 
V0  4.50  4.50  4.50  4.50  4.50 
V1  2.25  4.50  6.74  7.29  8.55 
V2  1.68  4.50  5.07  4.49  1.64 
V3  1.37  4.50  6.64  7.29  5.09 
V4  1.16  4.50  5.22  4.49  8.40 
V5  1.01  4.50  6.57  7.29  2.13 
V6  0.89  4.50  5.32  4.49  6.18 
V7  0.80  4.50  6.52  7.29  7.35 
V8  0.73  4.50  5.38  4.49  5.12 
V9  0.67  4.50  6.48  7.29  8.39 
The values of R in Table 2 are obtained by scaling the R values of Table I by 1/Vm = 1/9. For example, R = 2/9= .222 is the superstable growth factor and Rcr = 3.24/9 =.36 is the critical factor. In the case of Poissondistributed processes, the expected number of occurrences C = NP (large N, small fraction P of occurrence) is both the variance and mean of the distribution. A conditional Poisson process that conformed to this simple nonlinear model has the variance Ct + 1 = RCt (Cm Ct) and would be stable in growth rate range 1/Cm < R < 3/Cm where Cm is the specified maximum number of occurrences. When Ct = Cm/2 and R = 2/Cm the process is superstable^{1} and ideally Poisson because the expected number of occurrences Co = C1 = C2….= Ct = Ct + 1 remain constant and are time independent over the operating lifetime of the process. This condition of superstability is analogous to “States of Equilibrium” in Statistical Mechanics^{2} and is illustrated by the Ct + 1 = Ct intersecting line of above Figure I quadratic map.
The hypothetical model is suggestive of an ideal, superstable six sigma process with an expected Poisson failure no of C = 1.7 PPM (N= 106, P= 1.7 x 106), maximum failure number of Cm = 3.4 PPM and growth factor that has the value R = .60.
A realworld stable process would of course exhibit random fluctuations in variance which would not be strictly deterministic. However, as it ages or deteriorates and becomes unstable some deterministic chaos may be present and evident by an oscillatory pattern of variance (e.g., machine tool wear). If a process is stable with a relatively constant variance and it meets requirements (in my opinion) it does not need to be fixed.


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Comments
I think this article would benefit by adding a variable description and meaning. In the case that someone is new, it makes it clearer. Arguing a sophisticated point with someone in the know is makes it clearer.