An organization is always successful in its journey towards business excellence if it has specific goals for each of its critical processes. Various quality management programs adopted and implemented by such an organization can streamline the activities towards the ultimate goal of business excellence. When the quality improvement program is Six Sigma, the goal for the organization is obvious – to reach a sigma level of six, or the wellknown objective of 3.4 defects per million opportunities (DPMO). An organization operating at that level is described by Six Sigma proponents as being world class.
Many organizations may call themselves Six Sigma organizations as they start to implement various improvement tools of a typical Six Sigma program. But they really are not Six Sigma organizations in the sense of being world class (Table 1) until they are operating at, or at least closing in on, the goal of 3.4 DPMO. The reality is an organization can have difficulty telling exactly where it stands overall in terms of sigma level. That is because some of its critical processes are more important to its operations than others. And the sigma levels of all processes at any one time are unlikely to be the same.
Table 1: Classification of an Organization Using Sigma Level  
Sigma 
 Category 
6  3.4  World class 
5 4 3  230 6,200 67,000  Industry average 
2 1  310,000 700,000  Noncompetitive 
An approach is available to obtain the overall sigma level of an organization based on weighting each of the critical processes. Thus if a unit produced by a higherweighted critical process is found defective, then obviously such a defective unit costs more for the operation than a defect from a lowerweighted process. This method develops a link between each critical process and the DPMO and determines an overall weightbased sigma level.
Several possible cases are explored by assigning arbitrary values to weighted processes and sigma levels to illustrate how the overall sigma level of an organization can be obtained.
In many surveyrelated studies on performance of organizations with regard to customer satisfaction, an organization is said to have achieved or exceeded the level of customer satisfaction, if its average score is greater than or equal to 5 when the survey is conducted using a Likert scale of 1 to 10 (1 being not satisfied and 10 being extremely satisfied). The very purpose of the quality function deployment (QFD) tool is to prioritize various processes based on the importance ratings obtained as a result of customer satisfaction and/or customer requirement surveys.
For the Malcolm Baldrige National Quality Award criteria, weights are given to each of the critical success factors (dimensions) depending on their importance. For example, according to the award’s 2004 criteria, the factors “strategic planning,” “customer and market focus,” “human resource focus” and “process management” are each given the weight of 85 points (8.5 percent), the factor “measurement, analysis and knowledge management” is allotted a weight of 90 points (9 percent), the factor “leadership” has a weight of 120 points (12 percent) and the factor “business results” is given the maximum of 450 points (45 percent). Hence, the attempt to adopt this aspect in categorizing all the critical processes of an organization by giving specific weights to them in a clear way so as to obtain an overall weightbased sigma level of the organization at a given point of time.
Let us consider x_{i} (i = 1, 2, … , n) are the n critical processes identified by the organization of interest. At a point of time, let k_{1}, k_{2}, …, k_{n} are the sigma levels of the processes x_{1}, x_{2}, … , x_{n} respectively. Extensive study on the importance of these processes may reveal specific weights for the critical processes. Let w_{1}, w_{2}, …, w_{n} be the weights assigned to the respective processes such that:
This implies that the process x_{i} assumes a weight w_{i} to each unit produced, either defective or nondefective. Now the overall sigma level of an organization with regard to all n critical processes is obtained by using the information from Table 2.
Table 2: Weighted Defects Per Million Opportunities  
Critical  Weight  Sigma  DPMO  WeightedDPMO 
x_{1}  w_{1}  k_{1}  p_{1}  (w_{1}) × p_{1} 
x_{2}  w_{2}  k_{2}  p_{2}  (w_{2}) × p_{2} 
.  .  .  .  . 
x_{n}  w_{n}  k_{n}  p_{n}  (w_{n}) × p_{n} 
The total weightedDPMO from all the processes put together is obtained as:
The overall sigma level is now obtained for this combined DPMO either from the available tables or using the NORMSINV function available in Microsoft Excel. This sigma level is compared with Table 1 to determine the category in which the organization falls.
For a typical organization, a critical process may be highervalued or equallyvalued or lowervalued relative to other critical processes. This aspect may be easily visualized from the Baldrige criteria in which the dimensions are weighed differently or from QFD application in which relative ratings are used to prioritize the processes or process parameters for improvement. Hence, in a given set of critical processes that are used to determine the organization’s overall sigma level, all critical processes may be in the equallyvalued category or few may be in the highervalued category and hence the remaining are in the lowervalued category. Let us assume, without loss of generality that in case of equallyvalued n processes the weights are equal (1/n) and hence a weight 1/n is assigned to each unit produced by any of these n processes. Obviously, when the weights are equal, we get only the average of the DPMO values as the total weightedDPMO. However, the overall sigma level that we get ultimately is not the average of the corresponding sigma levels (refer to Tables 4, 5 and 6). When few processes (say, m < n) are highervalued, then the weight assumed for each of the m such highervalued processes is apparently more than that of the individual lowervalued processes. Under these circumstances the combinations shown in Table 3 may be expected.
Table 3: Process Types, Weights and Possible Sigma Levels  
Process Type  Weight  Sigma Level  
EquallyValued  1/n  Higher Sigma Level  Lower Sigma Level 
HigherValued  w_{i} > w_{j} *  Higher Sigma Level  Lower Sigma Level 
LowerValued  w_{j} < w_{i} *  Higher Sigma Level  Lower Sigma Level 
* w_{i} is the weight of the ith highervalued process out of m such processes and w_{j} is the weight of the jth lowervalued process out of n – m such processes.
In this study we are assuming that there are five critical processes (A, B, C, D and E) identified by an organization that alone are contributing to the maximum in its journey towards Six Sigma quality and hence are having an ultimate goal of achieving business excellence. Various arbitrary weights and sigma levels are chosen in different combinations to the critical processes in order to illustrate how an overall weightbased sigma level can be calculated for the organization. Though any combination is possible, only the following six cases are considered in this numerical study (Tables 49):
Case I: All processes are equallyvalued and resulted in higher sigma levels.
In this case, all the five processes are treated as equally important and hence each process is assumed a weight 1/5. We have considered higher (above 5) sigma levels for all the five processes. The overall sigma level is calculated using the data provided in Table 4.
Table 4: Equallyvalued Processes (Higher Sigma Levels)  

 Sigma  DPMO  WeightedDPMO 
A  1/5 (20%)  6  3.4  0.68 
B  1/5 (20%)  6  3.4  0.68 
C  1/5 (20%)  6  3.4  0.68 
D  1/5 (20%)  5.5  31.69  6.338 
E  1/5 (20%)  5.25  88.44  17.688 
From Table 4, we get total weightedDPMO equal to:
Let q = 26.066/1000000 = 0.000026066. Then the sigma quality level, k =1.5 + NORMSINV (1 – 0.000026066) = 1.5 + 4.046 = 5.546. Note that since equal weights are assigned, 26.066 ppm is nothing but the average of the respective DPMO values but 5.546 is not an average of the respective sigma levels. We conclude that the organization has achieved an overall sigma level of 5.546 and this falls in to the category of world class. On the other hand if we simply add the DPMO values the total becomes 130.33 ppm whose sigma quality level k = 1.5 + NORMSINV (1 – 0.00013033) = 1.5 + 3.652 = 5.152 which seems not reasonable.
Case II: All processes are equallyvalued and resulted in lower sigma levels.
In Case II, all the five processes are treated as equally important and hence each process is assumed a weight 1/5. However, we have considered lower (between 3 and 5) sigma levels for all the five processes. The overall sigma level is calculated using the data provided in Table 5.
Table 5: Equallyvalued Processes (Lower Sigma Levels)  

 Sigma  DPMO  WeightedDPMO 
A  1/5 (20%)  5  232.67  46.534 
B  1/5 (20%)  4  6,209.70  1,241.940 
C  1/5 (20%)  3  66,810.63  13,362.126 
D  1/5 (20%)  3.5  22,750.35  4,550.070 
E  1/5 (20%)  4.5  1,349.97  269.994 
From Table 5, we get total weightedDPMO equal to:
Let q = 19470.664/1000000 = 0.019470664. Then the sigma quality level, k =1.5 + NORMSINV (1 – 0.019470664) = 1.5 + 2.065 = 3.565. Hence, we conclude that the organization has achieved an overall sigma level of 3.565 and this falls in to the category of industry average.
Case III: All processes are equallyvalued and two resulted in higher sigma levels and three resulted in lower sigma levels.
In case III, all the five processes are treated as equally important and hence each process is assumed a weight 1/5. We have considered two processes with higher sigma levels and the remaining three with lower sigma levels. The overall sigma level is calculated using the data provided in Table 6.
Table 6: Equallyvalued Processes (Two Higher Sigma and Three Lower Sigma Levels)  

 Sigma  DPMO  WeightedDPMO 
A  1/5 (20%)  6  3.4  0.68 
B  1/5 (20%)  6  3.4  0.68 
C  1/5 (20%)  3  66,810.63  13,362.126 
D  1/5 (20%)  3.5  22,750.35  4,550.070 
E  1/5 (20%)  4.5  1,349.97  269.994 
From Table 6, we get total weightedDPMO equal to:
Let q = 18183.55/1000000 = 0.01818355. Then the sigma quality level, k =1.5 + NORMSINV (1 – 0.01818355) = 1.5 + 2.093 = 3.593. Hence, we conclude that the organization has achieved an overall sigma level of 3.593 and this falls in to the category of industry average. Note that in this case the organization is not coming under the category of worldclass though it has achieved sixsigma level in two of the five critical processes.
Case IV: Two processes are highervalued and three processes are lowervalued and all resulted in higher sigma levels.
In this case, two processes are treated as highervalued with a weight of 0.30 each and the remaining three as lowervalued with weights 0.10 and 0.15. We have considered higher sigma levels for all the five processes. The overall sigma level is calculated using the data provided in Table 7.
Table 7: Two HigherValued and Three LowerValued Processes (Higher Sigma Levels)  

 Sigma  DPMO  WeightedDPMO 
A  0.30 (30%)  6  3.4  1.02 
B  0.15 (15%)  6  3.4  0.51 
C  0.10 (10%)  6  3.4  0.34 
D  0.15 (15%)  5.5  31.69  4.7535 
E  0.30 (30%)  5.25  88.44  26.532 
From Table 7, we get total weightedDPMO equal to:
Let q = 33.1555/1000000 = 0.0000331555. Then the sigma quality level, k =1.5 + NORMSINV (1 – 0.0000331555) = 1.5 + 3.989 = 5.489. Hence, we conclude that the organization has achieved an overall sigma level of 5.489 and this falls in to the category of world class.
Case V: Two processes are highervalued and three processes are lowervalued and all resulted in lower sigma levels.
In case V, two processes are treated as highervalued with a weight of 0.30 each and the remaining three as lowervalued with weights 0.10 and 0.15. We have considered lower sigma levels for all five processes. The overall sigma level is calculated using the data provided in Table 8.
Table 8: Two Highervalued and Two Lowervalued Processes (Lower Sigma Levels)  

 Sigma  DPMO  WeightedDPMO 
A  0.30 (30%)  5  232.67  69.801 
B  0.15 (15%)  4  6,209.70  931.455 
C  0.10 (10%)  4  66,810.63  6,681.063 
D  0.15 (15%)  3.5  22,750.35  3,412.5525 
E  0.30 (30%)  4.5  1,349.97  404.991 
From Table 8, we get total weightedDPMO equal to:
Let q = 11499.8625/1000000 = 0.0114998625. Then the sigma quality level, k =1.5 +NORMSINV (1 – 0.0114998625) = 1.5 + 2.273 = 3.773. Hence, we conclude that the organization has achieved an overall sigma level of 3.773 and this falls in to the category of industry average.
Case VI: Two processes are highervalued and three processes are lowervalued and two resulted in higher sigma levels and three resulted in lower sigma levels.
In case VI, two processes are treated as highervalued with a weight of 0.30 each and the remaining three as lowervalued with weights 0.10 and 0.15. We have considered two processes with higher sigma levels and the remaining three with lower sigma levels. The overall sigma level is calculated using the data provided in Table 9.
Table 9: Two Highervalued and Two Lowervalued Processes (Two Higher Sigma and Three Lower Sigma Levels)  

 Sigma  DPMO  WeightedDPMO 
A  0.30 (30%)  6  3.4  1.02 
B  0.15 (15%)  6  3.4  0.51 
C  0.10 (10%)  6  66,810.63  6,681.063 
D  0.15 (15%)  3.5  22,750.35  3,412.5525 
E  0.30 (30%)  4.5  1,349.97  404.991 
From Table 9, we get total weightedDPMO equal to:
Let q = 10500.1365/1000000 = 0.0105001365. Then the sigma quality level, k =1.5 +NORMSINV (1 – 0.0105001365) = 1.5 + 2.308 = 3.808. Hence, we conclude that the organization has achieved an overall sigma level of 3.808 and this falls in to the category of industry average. Note that in this case the organization is not coming under the category of world class though it has achieved sixsigma level in two of the five critical processes.
When it implements a quality improvement program, an organization would like to monitor its progress at every given point of time. And, the organization notes the milestones it crosses on its journey toward business excellence. When it is a Six Sigma quality program, the milestones are the sigma levels that the organization achieves by its implementation. Obviously the organization aims for the Six Sigma goal of 3.4 DPMO. Such an organization is often referred to as a Six Sigma organization. Since, an organization can identify many critical processes that contribute to the Six Sigma status, the sigma levels of each of these processes contribute to the overall sigma level. However, each critical process may be at different levels of importance to the organization. The approach outlined here incorporates assigning weights to the critical processes and the corresponding DPMO values and hence it is effective in obtaining an accurate overall sigma level of an organization.


Comments
I went through the entire article and it was a great help as I am trying to calculate an overall Sigma for an Automated Medicine Dispensing Machine. However I wanted to know if there is any Formal Documentation/Paper/Examples on how to assign weights to your processes while calculating the overall Sigma. Can it be based on amount of product handled by each process? Thank you!
Hallo,
Thank you very much for your interest in my paper. You can see my other paper given below that may help you.
Cost based process weights for DPMO and the overall sigma level of an organization, Vol. 19,
No. 5, pp.442 – 453, 2007, Total Quality Management, Emerald Group.
Please feel free to revert back to me for any clarification/help.
Regards
I vehemently disagree. If a defect “isn’t important” then it isn’t really a defect. This approach is a feel good attempt to justify not addressing defects. Anything that doesn’t conform to the requirement is a defect. To reduce it to a “minor” defect (or elevate other defects by some multiple) does nothing to eliminate the defect, rather it tends to allow the defect to remain. Either the requirement was not specified correctly (often the case), it is being evaluated incorrectly, or it is an actual defect. Not all defects can be eliminated cost effectively, but that should not be the reason to reduce their impact. They should remain and should be reevaluated since technologies and approaches emerge that may overcome the costs.
I do not know about what you disagree. Also I am unable to understand what you are trying to convey. Though I accept any criticisms, please note that this method has been well received and appreciated by both practitioners and researchers.
Not all defects are equal. Some cause more problems/dissatisfaction than others, and so when dealing with them, it is appropriate to prioritize them. But a defect is still a defect, and degrading some in order to delude yourself that your quality level is better than it actually is, is just that – delusional.
Halo,
Thank you for your comment. I request you to please read the article carefully and understand that it is about what. There is no dispute that a defect is defect. It is all about weighing of of the processes based on their value: high value,low value etc.
Interesting approach.
I don’t know why one would want a DPMO of 6 processed combined into one DPMO number. The DPMO of the 6 is the power of figuring out where to work along with business needs and impact.
Dear Chrls,
Thanks for your mail and it is good that the method is an interesting one for you. In this method, in fact, the weighted DPMOs are computed processwise to determine the processwise sigma level. Then the total DPMO is obtained to get the overall sigma level of the organization running all the six processes. Now, we can say the sigma level of the organization as a whole for benchmarking with the competing organizations.
Regards
Dr.J.Ravichandran
Hi dear sir I am a very new learner of six sigma, as I read this method I was getting everything clear. But some issues I am not getting clear such as in table 6, for company D & E how can I select sigma level like why or how 3.5 or 4.5 and how to measure DPMO against that measure. Could you please show some calculation with example for my better . Oh your explanation and all this method helped me so much. Thanks a lot in advance for the further.